(2z-6)(z+2)=2z^2-38

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Solution for (2z-6)(z+2)=2z^2-38 equation:


Simplifying
(2z + -6)(z + 2) = 2z2 + -38

Reorder the terms:
(-6 + 2z)(z + 2) = 2z2 + -38

Reorder the terms:
(-6 + 2z)(2 + z) = 2z2 + -38

Multiply (-6 + 2z) * (2 + z)
(-6(2 + z) + 2z * (2 + z)) = 2z2 + -38
((2 * -6 + z * -6) + 2z * (2 + z)) = 2z2 + -38
((-12 + -6z) + 2z * (2 + z)) = 2z2 + -38
(-12 + -6z + (2 * 2z + z * 2z)) = 2z2 + -38
(-12 + -6z + (4z + 2z2)) = 2z2 + -38

Combine like terms: -6z + 4z = -2z
(-12 + -2z + 2z2) = 2z2 + -38

Reorder the terms:
-12 + -2z + 2z2 = -38 + 2z2

Add '-2z2' to each side of the equation.
-12 + -2z + 2z2 + -2z2 = -38 + 2z2 + -2z2

Combine like terms: 2z2 + -2z2 = 0
-12 + -2z + 0 = -38 + 2z2 + -2z2
-12 + -2z = -38 + 2z2 + -2z2

Combine like terms: 2z2 + -2z2 = 0
-12 + -2z = -38 + 0
-12 + -2z = -38

Solving
-12 + -2z = -38

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -2z = -38 + 12

Combine like terms: -12 + 12 = 0
0 + -2z = -38 + 12
-2z = -38 + 12

Combine like terms: -38 + 12 = -26
-2z = -26

Divide each side by '-2'.
z = 13

Simplifying
z = 13

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